[1/6x]^2-x-12=0

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Solution for [1/6x]^2-x-12=0 equation: 


Oblicz to!

(91/60)*x^2-x-12 = 0

-24/10 = 0

(1/3)*x-3 = 5-((3/2)*x)

(2*x)/5-(1/3) = 0

(2*x^3-4*x^4+12*x^2+2*x-4)/(((x^2-1)*(x+1))^2) = 0

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